Selecting a ratio
Match the two involved side roles to a trigonometric ratio
- Use the marked angle Name the given and wanted sides relative to that angle. The hypotenuse is always opposite the right angle
- Choose the matching pair Choose the ratio that contains both involved sides \(\displaystyle \begin{aligned}\sin\theta&=\frac{\text{opposite}}{\text{hypotenuse}}\\\cos\theta&=\frac{\text{adjacent}}{\text{hypotenuse}}\\\tan\theta&=\frac{\text{opposite}}{\text{adjacent}}\end{aligned}\)
- Recheck after an angle change The two shorter sides exchange roles when the marked acute angle changes. Check the pair again
Worked example
Choose a ratio for the stated given and wanted sides of a right triangle
- \(\displaystyle \begin{gathered}\text{involved pair:}\\\text{opposite and adjacent}\end{gathered}\)Both shorter sides are involved. The hypotenuse is not needed
- \(\displaystyle \tan\theta=\frac{\text{opposite}}{\text{adjacent}}\)Tangent contains exactly that pair, so choose tangent
Common mistakes
Difficulty levels
Questions about this topic
Does the unknown letter determine the ratio?+
No. Name both involved sides relative to the marked angle, then choose the ratio containing them
What changes when the other acute angle is marked?+
The shorter sides exchange opposite and adjacent roles. The hypotenuse stays the same
When do I use tangent?+
Use tangent when the known and wanted sides are the two shorter sides
Can I use a calculator?+
No. This topic is practised without a calculator
Which year level and chapter is this?+
Year 9 Mathematics, chapter 3: Pythagoras and trigonometry