An explicit arithmetic rule
The index determines how many equal updates to add to the starting value
- Start at zero There are n updates \(\displaystyle t_n=t_0+nd\)
- Start at one There are n − 1 updates \(\displaystyle t_n=t_1+(n-1)d\)
- Recover a difference Divide the change in value by the change in index
- Check the start Substitute the initial index into your rule
Worked example
An arithmetic sequence starts with t₀ = 9 and adds −2 each step. Find t₆
- \(\displaystyle t_n=9-2n\)The constant is the initial value and the coefficient is the difference
- \(\displaystyle t_6=9-2\times6\)There are six updates from index zero
- \(\displaystyle t_6=-3\)Keep the negative result
Common mistakes
Difficulty levels
Questions about this topic
Why does the starting index matter?+
The number of updates is the difference between the required index and the starting index
Is a recurrence an explicit rule?+
No. A recurrence uses earlier terms. An explicit rule calculates directly from the index
Can the difference be zero?+
Yes. Then every term equals the initial value
Can I use a calculator?+
A calculator is allowed unless a question is marked no calculator
Which year level and chapter is this?+
Year 11, VCE Units 1 & 2, General Mathematics, chapter 3: Sequences and finance