Find and extend a sequence rule
Test the stated class of rules rather than assuming the first difference always works
- Additive check Calculate the changes across consecutive pairs \(\displaystyle 9-5=4,\quad13-9=4\)
- Multiplicative check Divide each later value by the one before it \(\displaystyle 12/8=18/12=3/2\)
- Extend from the latest value Use each new result as the input to the next application \(\displaystyle 27\times(3/2)=40.5\)
Worked example
Use a constant additive or multiplicative rule to extend 6, 9, 13.5, 20.25
- \(\displaystyle 9-6=3\)The first additive change is 3.
- \(\displaystyle 13.5-9=4.5\)The changes differ, so test ratios
- \(\displaystyle 9/6=1.5\)Test the first ratio
- \(\displaystyle 13.5/9=1.5\)The next ratio is the same
- \(\displaystyle 20.25/13.5=1.5\)All three transitions multiply by 1.5
- \(\displaystyle 20.25\times1.5=30.375\)Use the latest displayed term
Common mistakes
Difficulty levels
Questions about this topic
Can multiplication make positive values smaller?+
Yes. A multiplier between zero and one decreases a positive value. For example, multiplying by one half halves it
Is multiplying by three halves the same as dividing by 2?+
No. Multiply by 3 and divide by 2, or multiply by 1.5. Dividing by 2 alone is multiplication by one half
Why check more than one pair?+
One transition may fit several operations. A proposed rule must fit every displayed transition
Can I use a calculator?+
A calculator is allowed unless a question is marked no calculator
Which year level and chapter is this?+
Year 11, VCE Units 1 & 2, General Mathematics, chapter 3: Sequences and finance