Properties of Pearson's r
Pearson's r summarises the direction and strength of a linear association between two numerical variables. Its value is bounded, its sign gives direction, and its magnitude gives linear strength
- Defined values For paired numerical observations with nonzero variation in each variable, −1≤r≤1. Pearson’s r is unitless and measures linear association. A constant variable makes its ordinary denominator zero, so r is undefined
- Interpret the display Inspect the scatterplot before summarising. A coefficient can be calculated for a nonconstant curved dataset, but it can miss that relationship. Near-zero r does not rule out a strong non-linear pattern. Investigate unusual cases and separate groups without automatically deleting them
- Separate sign, strength and cause Use sign for linear direction and magnitude for linear strength. Steepness depends on units. Correlation is unchanged by swapping the two lists, but the explanatory/response question still matters. Neither a large coefficient nor a precise calculation establishes causation
- Declared practice convention For these exercises only, use |r|<0.25: the bank label “No association”; 0.25≤|r|<0.50: weak; 0.50≤|r|<0.75: moderate; 0.75≤|r|≤1: strong. The sign supplies direction outside the first bin. These are reporting conventions, not universal boundaries. The first label means little or no linear association under this convention; it does not prove no relationship or independence. At |r|=1 also state perfect linear association
Worked example
A numerical data set has Pearson's correlation coefficient r = -0.64. State whether the value is possible and classify the direction and strength of the linear association
- \(\displaystyle -1\le-0.64\le1\)The value lies in the inclusive range, so it is possible for Pearson's r.
- \(\displaystyle r<0\Rightarrow\text{negative direction}\)The negative sign means the response tends to decrease as the explanatory variable increases
- \(\displaystyle \lvert-0.64\rvert=0.64,\quad0.5\le0.64<0.75\Rightarrow\text{moderate strength}\)The magnitude 0.64 is in the moderate band, so the association is moderate negative and linear
Common mistakes
Difficulty levels
Questions about this topic
What values can Pearson's r take?+
Pearson's r can take any value from -1 to 1 inclusive. Values of -1 and 1 represent perfect linear associations
What do the sign and magnitude of r show?+
The sign gives the direction of the linear association. The magnitude gives its strength, with values closer to 1 in magnitude showing a tighter linear pattern
When is Pearson's r suitable?+
Use it for two numerical variables with an approximately linear association. It is sensitive to influential outliers, especially in a small data set
Can a curved dataset have a numerical r?+
Yes, if both numerical variables vary. The result measures only the linear part and may be a poor summary of the curved relationship. Inspect the plot
Does a constant column give r=0?+
No. Its variance is zero, so ordinary Pearson correlation is undefined
Can a horizontal model exist when correlation is undefined?+
Yes. With variation in x and a constant response, the horizontal line at that response has zero residuals. Ordinary Pearson correlation remains undefined because the response spread is zero
Does this preliminary check finish model assessment?+
No. Fit the model, inspect residuals and consider the investigation context and supported range before using it. Later sections develop those steps
Can I use a calculator?+
A calculator is allowed unless a question is marked no calculator
Which year level and chapter is this?+
Year 12, VCE Units 3 & 4, General Mathematics, chapter 3: Linear regression