State order and locate elements
The order gives rows first and columns second. In a named element, the first subscript selects the row and the second subscript selects the column
- Write rows before columns Count the horizontal rows first and the vertical columns second \(\displaystyle \text{order}=3 \times 2\)
- Read the first subscript as the row For an entry, the first subscript i gives the row and the second subscript j gives the column \(\displaystyle a_{23}=\text{row 2, column 3}\)
- Count entries by multiplication Multiply the number of rows by the number of columns to find the number of entries \(\displaystyle 3 \times 2=6\)
- Do not count labels as entries Only the data inside the matrix is included in the order and entry count \(\displaystyle \text{data order}=2 \times 3\)
Worked example
The matrix B is given below. State its order, count its entries and find the requested element
- \(\displaystyle \text{order of }B=2 \times 3\)Matrix B has two rows and three columns
- \(\displaystyle 2 \times 3=6\)The matrix therefore has 6 entries
- \(\displaystyle b_{23}=\text{row 2, column 3}\)The first subscript selects row 2 and the second selects column 3
- \(\displaystyle b_{23}=2\)The entry in row 2, column 3 is 2
Common mistakes
Difficulty levels
Questions about this topic
Why are rows written first in the order?+
The convention for matrix order is rows multiplied by columns, so a matrix with m rows and n columns has order m by n
How do the two subscripts identify an entry?+
It means the entry in row i and column j. The row number is read before the column number
How is the number of entries found?+
Multiply the number of rows by the number of columns. A 2 by 3 matrix has 6 entries
Can I use a calculator?+
No. This topic is practised without a calculator
Which year level and chapter is this?+
Year 11, VCE Units 1 & 2, General Mathematics, chapter 4: Matrices