Equation from a graph
Read the intercept, calculate the gradient and place both in the equation
- Intercept Read the vertical coordinate at the vertical-axis crossing \(\displaystyle (0,c)\)
- Gradient Use signed coordinate changes in the same direction \(\displaystyle m=\frac{y_2-y_1}{x_2-x_1}\)
- Notation The order of the terms may change without changing their roles \(\displaystyle mx+c=c+mx\)
- Check Substitute another visible point into the completed equation
Worked example
Use the vertical-axis crossing and the other supplied point to find the equation
- \(\displaystyle c=-5\)The first point is on the vertical axis
- \(\displaystyle m=\frac{4-(-5)}{6-0}\)Use the vertical change divided by the horizontal change
- \(\displaystyle m=\frac{9}{6}\)Evaluate the two changes
- \(\displaystyle m=\frac{3}{2}\)Write the gradient as an exact fraction
- \(\displaystyle y=\frac{3}{2}x-5\)Place the two coefficients in the equation
- \(\displaystyle \begin{aligned}\frac{3}{2}(6)-5&=9-5\\&=4\end{aligned}\)The second point's vertical coordinate is reproduced
Common mistakes
Difficulty levels
Questions about this topic
Is the left edge the vertical axis?+
Only when the horizontal coordinate there is zero. Use the scale, not the frame
What if the intercept is outside the picture?+
Use two points to find the gradient, then substitute a point to recover the intercept. The later two-point topic combines those steps
Can the gradient be zero?+
Yes. A horizontal line has the same vertical coordinate at every point
Can I use a calculator?+
A calculator is allowed unless a question is marked no calculator
Which year level and chapter is this?+
Year 11, VCE Units 1 & 2, General Mathematics, chapter 5: Linear functions and models