Iterating a first-order recurrence
A first-order recurrence generates a sequence by using the current term in a fixed rule. Start at V_0, then apply the rule once for each increase in the index
- Start at the initial term Use V_0 as the starting value and treat its index as zero \(\displaystyle V_0=5\)
- Identify the two roles In aV_n+b, a multiplies the current term and b is the fixed change added after multiplication \(\displaystyle V_{n+1}=2V_n-1\quad\Rightarrow\quad a=2,\ b=-1\)
- Use the preceding term Each new term is calculated from the term immediately before it, not repeatedly from V_0. \(\displaystyle V_1=2(5)-1=9,\quad V_2=2(9)-1=17\)
- Count applications from zero The index n records the number of rule applications after V_0. \(\displaystyle V_0\xrightarrow{1\text{ application}}V_1\xrightarrow{2\text{ applications}}V_2\)
Worked example
A sequence is indexed from zero. Find the term at index 3 by iterating the recurrence shown
- \(\displaystyle V_1=2(3)+4=10\)Apply the rule once to the initial term to find V_1.
- \(\displaystyle V_2=2(10)+4=24\)Use V_1 as the current input for the second transition
- \(\displaystyle V_3=2(24)+4=52\)Use V_2 for the third transition, giving V_3=52.
Common mistakes
Difficulty levels
Questions about this topic
What does the index n count in a recurrence sequence?+
It counts the number of rule applications after the initial term V_0. Thus V_1 is one application and V_2 is two applications
What is the difference between a and b in V_{n+1}=aV_n+b?+
The number a multiplies the current term, while b is the fixed amount added after that multiplication
Why must each term use the preceding term?+
A first-order recurrence is defined by its immediately previous term. Reusing V_0 would repeat the first calculation instead of generating the sequence
Can I use a calculator?+
A calculator is allowed unless a question is marked no calculator
Which year level and chapter is this?+
Year 12, VCE Units 3 & 4, General Mathematics, chapter 7: Recursion and financial models