Clear fractions without losing restrictions
Use equivalent linear-equation transformations after the denominators have been cleared
- Restrictions first Record zeroes of the original denominators before clearing
- Common denominator Include all required denominator factors. For numbers, use the least common multiple
- Multiply every term Use the same LCD on both sides, including whole-number terms. This is valid only where the LCD is nonzero
- Solve then check Expand brackets, collect terms and isolate the unknown. Reject forbidden candidates and check both original sides
Worked example
Solve, retaining the original restriction
- \(\displaystyle x\ne1\)The original denominator must be nonzero
- \(\displaystyle 4+2(x-1)=6(x-1)\)Multiply every term by the denominator at allowed inputs
- \(\displaystyle 4+2x-2=6x-6\)Expand both brackets
- \(\displaystyle 8=4x\)Collect the unknown terms on the right and constants on the left
- \(\displaystyle x=2\)Divide by 4. The candidate is allowed
- \(\displaystyle \frac4{2-1}+2=6\)Substitution verifies the original equation
Common mistakes
Difficulty levels
Questions about this topic
Why record restrictions before clearing?+
Cancelling a denominator can hide the inputs where the original expression was undefined
Must a polynomial LCD be positive?+
No. It must contain the denominator factors and be nonzero at allowed inputs. The numerical least common multiple is chosen positive
Can clearing create a false candidate?+
Yes. A root of the cleared equation may be excluded by an original denominator. Reject it
When can I cross-multiply?+
When one fraction equals one fraction, with both denominators nonzero. For sums, multiply every term by a common denominator
Why check the original equation?+
It checks arithmetic and domain restrictions together. A cleared equation alone can hide an undefined input
Can I use a calculator?+
No. This topic is practised without a calculator
Which year level and chapter is this?+
Year 10 Mathematics, chapter 8: Linear equations and inequalities