Connect graphs and simultaneous solutions
A solution is a pair that lies on both lines and satisfies both original equations
- Choose the ready subject Use the equation that already has an unknown isolated. Either unknown can be the subject
- Replace the whole expression Insert the expression into the other equation. Bracket it when it is multiplied or subtracted
- Solve, then substitute back Solve the resulting equation. Use that value to find the remaining unknown
- Use both original equations Check the same pair in both. A pair that works in only one equation is not a simultaneous solution
- Same subject in both equations Equate the expressions for that subject, then solve and substitute back
- Classify first when useful Different gradients give one point. Equal gradients and different intercepts give no points. Equivalent equations give one whole common line
- Interpret cancellation A contradiction means no solution. An identity means the two line equations are equivalent, so infinitely many pairs lie on their common line
Worked example
Solve the simultaneous pair
- \(\displaystyle 6+\frac{x}{2}=2-\frac{3x}{2}\)Equate the expressions for the shared unknown
- \(\displaystyle 12+x=4-3x\)Multiply every term on both sides by the common denominator
- \(\displaystyle 12+4x=4\)Add the variable term from the right to both sides
- \(\displaystyle 4x=-8\)Subtract the constant on the left from both sides
- \(\displaystyle x=-2\)Divide both sides by the coefficient
- \(\displaystyle y=6+\frac{-2}{2}\)Substitute into the first original equation
- \(\displaystyle y=5\)Calculate the other unknown
- \(\displaystyle 6+\frac{-2}{2}=5\)The first original equation gives the required value
- \(\displaystyle 2-\frac{3(-2)}{2}=5\)The second original equation gives the same value
- \(\displaystyle (x,y)=(-2,5)\)State the two values in the named order
Common mistakes
Difficulty levels
Questions about this topic
Must both equations have an unknown isolated?+
No. One ready subject is enough. Replace that unknown in the other equation with the whole expression
Why use brackets around the replacement?+
Brackets show that a coefficient or subtraction applies to every term in the expression
Why do I need to find both values?+
A simultaneous solution gives a value for each unknown. Check those same values in both original equations
What if both equations already have the same subject?+
Set their expressions equal. They must have the same value at the solution
Does infinitely many solutions mean every pair works?+
No. Only pairs on the shared line work. There are infinitely many of them, but other points in the plane do not satisfy the equations
Is one shared point enough to prove two lines are identical?+
No. Different nonparallel lines share one point. Equivalent equations or two distinct shared points establish that two straight lines coincide
Can I use a calculator?+
A calculator is allowed unless a question is marked no calculator
Which year level and chapter is this?+
Year 10 Mathematics, chapter 8: Linear equations and inequalities