Evaluating base-10 logarithms
A base-10 logarithm records the exponent needed to produce a positive number from 10. Powers of ten can be evaluated exactly, while other positive values use technology and the stated rounding
- Interpret a logarithm as an exponent The base-10 logarithm is the exponent that produces the positive number \(\displaystyle 10^3=1000\Rightarrow\log_{10}(1000)=3\)
- Use the exact power when available Integer powers of ten give integer logarithms, including log₁₀(1) = 0. \(\displaystyle \log_{10}(1)=0,\quad \log_{10}(100000)=5\)
- Use technology for other positive values A positive value that is not an integer power of ten is evaluated with technology and rounded at the stated precision \(\displaystyle \log_{10}(200)\approx2.301\text{ to 3 d.p.}\)
- Reverse a logarithm with an antilogarithm If the logarithm is known, raise 10 to that power to recover the number \(\displaystyle \log_{10}(2.5)\approx0.398,\quad 10^{2.5}\approx316.228\)
Worked example
Evaluate the logarithm and the reverse logarithmic expression. Give the second answer to 3 decimal places
- \(\displaystyle 10000=10^4\)Write the first number as a power of 10.
- \(\displaystyle \log_{10}(10000)=4\)The logarithm is the exponent in the power of 10.
- \(\displaystyle 10^{2.5}=316.227766\ldots\)Evaluate the antilogarithm with technology before rounding
- \(\displaystyle 10^{2.5}\approx316.228\)Rounding 316.227766... to 3 decimal places gives 316.228
Common mistakes
Difficulty levels
Questions about this topic
What does log₁₀(a) mean?+
It is the exponent n such that 10ⁿ = a, provided a is positive
Why is log₁₀(1) equal to 0?+
The zeroth power of any non-zero number is 1, so ten to the zeroth power is one and the base-10 logarithm of one is zero
How is an antilogarithm found?+
If the base-10 logarithm of N is L, raise ten to the power L to find N. Use technology and the stated rounding when L is not an integer
Can I use a calculator?+
A calculator is allowed unless a question is marked no calculator
Which year level and chapter is this?+
Year 11, VCE Units 1 & 2, General Mathematics, chapter 9: Variation