The determinant of a 2 × 2 matrix
For a 2 × 2 matrix, the determinant compares the products along its two diagonals. Keep the order of the subtraction because it determines the sign
- Name the entries Use a = 4, b = 2, c = 5 and d = 3 in row order for this example \(\displaystyle A=\begin{bmatrix}4&2\\5&3\end{bmatrix}\)
- Multiply the leading diagonal Multiply the top-left entry by the bottom-right entry \(\displaystyle ad=4\times3=12\)
- Multiply the other diagonal Multiply the top-right entry by the bottom-left entry \(\displaystyle bc=2\times5=10\)
- Subtract in order Subtract the other-diagonal product from the leading-diagonal product \(\displaystyle \det(A)=ad-bc=12-10=2\)
Worked example
Find the determinant of the matrix B.
- \(\displaystyle 7\times3=21\)The leading-diagonal product is 7 × 3 = 21.
- \(\displaystyle \left(-2\right)\times4=-8\)The other-diagonal product is (−2) × 4 = −8.
- \(\displaystyle \det(B)=21-\left(-8\right)=29\)Subtracting the negative other-diagonal product gives 21 + 8 = 29.
Common mistakes
Difficulty levels
Questions about this topic
Why is the determinant ad − bc rather than ad + bc?+
The 2 × 2 determinant rule is defined as the leading-diagonal product minus the other-diagonal product. Adding the products gives a different value
What does a determinant of zero tell you?+
A 2 × 2 matrix with determinant zero has no inverse because the inverse rule would require division by zero
How should negative entries be handled?+
Keep the signs while calculating both products. Subtracting a negative product is equivalent to adding its magnitude
Can I use a calculator?+
No. This topic is practised without a calculator
Which year level and chapter is this?+
Year 12, VCE Units 3 & 4, General Mathematics, chapter 10: Matrices