Expected value and linear expectation of a discrete random variable
A discrete rule assigns a point total to each outcome
Let \(X\) be the discrete random variable in the table below
The probability mass function for the stated values is
\[p(x)=\frac{-x+2}{12}\]
| \(x\) | \(\Pr(X=x)\) | \(x\Pr(X=x)\) |
|---|---|---|
| \(-3\) | \(\frac{5}{12}\) | \(\square\) |
| \(-2\) | \(\frac{1}{3}\) | \(-\frac{2}{3}\) |
| \(-1\) | \(\frac{1}{4}\) | \(\square\) |
Determine \(E(X)\) from the distribution