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Question 1 of 8

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Consider the circular equation shown below

\[\sin x=-0.125x + 0.582\]

Write the algebraic function in the equation as \(P(x)=-0.125x + 0.582\)

Let \(F(x)\) be the circular side minus the algebraic side, so \(F(x)=\sin x-\left(-0.125x + 0.582\right)\)

The sign-changing interval under consideration is \(\left[\frac{3}{10},\frac{9}{10}\right]\). The table also gives one point just outside each endpoint

The displayed function values are rounded to 3 decimal places; their signs are retained
\(x\)\(F(x)\)
\(\frac{3}{20}\)\(\approx -0.414\)
\(\frac{3}{10}\)\(\approx -0.249\)
\(\frac{9}{10}\)\(\approx 0.314\)
\(\frac{21}{20}\)\(\approx 0.417\)

Use the endpoint signs in the table to identify what can be concluded about a root

Select the two functions, the justified root count and the interval containing the sign change

(a)1 mark

Which pair of functions is being compared in the equation?

(b)1 mark

What root-count conclusion is justified by the supplied evidence?

(c)1 mark

Which interval has an endpoint sign change?