Probabilities of sequences of independent events
Independent sensor readings are classified into two outcomes
A success is a reading in the target class. Let \(E_i\) denote success on trial \(i\)
The trial outcomes are independent, and the sample space is \(S\)
The exact success probabilities are \(\Pr(E_i) = \frac{3}{8} \,\text{ for every trial}\)
Let \(A\) be the event that no trial is a success
\[A = E_{1}′\cap E_{2}′\cap E_{3}′\cap E_{4}′\]