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Solve simultaneous equations by elimination

Question 1 of 8

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The two equations are shown below. Solve the simultaneous equations by elimination

a - 2b = 20

-3a + 2b = -32

The equations are numbered in the order shown

(a)1 mark

Select the correct elimination calculation. Eliminate \(b\) first

\begin{aligned}&(3a - 6b)\\&+(-3a + 2b)\\&=(60)+(-32)\end{aligned}

\begin{aligned}&(a - 2b)\\&+(-3a + 2b)\\&=(20)+(-32)\end{aligned}

\begin{aligned}&(a - 2b)\\&-(-3a + 2b)\\&=(20)-(-32)\end{aligned}

\begin{aligned}&(a - 2b)\\&+(-3a + 2b)\\&=-[(20)+(-32)]\end{aligned}

(b)1 mark

What is the value of \(a\)? Give the exact value

\(a\)

Format: exact value

What is the value of \(b\)? Give the exact value

\(b\)

Format: exact value