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Trigonometry in three dimensions

Question 1 of 8

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A rectangular frame has horizontal base edges AB = 5 m and BC = 10 m. G is directly above C, with vertical height CG = 5 m. AG is a straight brace to the opposite top corner

Projection. Cuboid projection and extracted section ACG. Base edges AB and BC are 5 m and 10 m. G is vertically 5 m above C. AC is the horizontal base diagonal f and AG is the spatial brace d. The section has a right angle at C. The angle to the base plane is CAG. Not to scale.5 m10 mdABCGRight-angled section. Cuboid projection and extracted section ACG. Base edges AB and BC are 5 m and 10 m. G is vertically 5 m above C. AC is the horizontal base diagonal f and AG is the spatial brace d. The section has a right angle at C. The angle to the base plane is CAG. Not to scale.f5 mdACGθ
Cuboid and section ACG. The angle to the base plane is at A, between AC and AG. Not to scale

Use the right-triangle section ACG. AC lies in the horizontal base plane and is perpendicular to CG. Keep intermediate values unrounded

(a)1 mark

Find the horizontal base diagonal AC to 1 decimal place

Format: 1 d.p.
(b)1 mark

Find the angle of elevation of the spatial brace from the horizontal base diagonal at the starting vertex. Give the angle to 1 decimal place

Format: 1 d.p.