Independent event sequences
Independent trials have no change in the probability of one trial caused by another. Multiply the probability of every required success or failure, and use a complement for an at-least-one event
- Multiply a specified pattern A pattern that requires an outcome at each trial uses one factor for each required result \(\displaystyle \Pr(S,F,S)=p_1(1-p_2)p_3\)
- Use the failure complement The probability of failure on a trial is one minus its success probability \(\displaystyle \Pr(E_i^{\prime})=1-p_i\)
- Use a complement for at least one At least one success is the complement of failure on every trial \(\displaystyle \Pr(\text{at least one})=1-(1-p)^n\)
- Use each trial's probability When success probabilities differ, use the probability belonging to each trial \(\displaystyle \Pr(S,F)=\frac{2}{3}\times\frac{1}{4}=\frac{1}{6}\)
Worked example
Four independent trials have success probabilities one half, two thirds, three quarters and one fifth. Find the probability of at least one success
- \(\displaystyle \Pr(E_1^{\prime})=\frac{1}{2},\quad\Pr(E_2^{\prime})=\frac{1}{3},\quad\Pr(E_3^{\prime})=\frac{1}{4},\quad\Pr(E_4^{\prime})=\frac{4}{5}\)Subtract each success probability from 1 to find the corresponding failure probability
- \(\displaystyle \Pr(\text{no successes})=\frac{1}{2}\times\frac{1}{3}\times\frac{1}{4}\times\frac{4}{5}=\frac{1}{30}\)Independence means that the four failure probabilities are multiplied
- \(\displaystyle \Pr(\text{at least one success})=1-\Pr(\text{no successes})=1-\frac{1}{30}=\frac{29}{30}\)Subtract the probability of no successes from 1.
Common mistakes
Difficulty levels
Questions about this topic
Why are probabilities multiplied for independent trials?+
Independence means that the required result on one trial does not change the probability on another trial. The joint pattern probability is therefore the product of its factors
How is the probability of at least one success found?+
Find the probability of failure on every trial, then subtract it from 1. Failure on every trial is the complement of at least one success
Why must failure factors be included in an only-success pattern?+
Only the named trials may succeed, so every other trial must fail. Each required failure contributes a factor of 1 minus its success probability
Can I use a calculator?+
No. This topic is practised without a calculator
Which year level and chapter is this?+
Year 11, VCE Units 1 & 2, Mathematical Methods, chapter 8: Probability and counting