Testing independence
Two events are independent when knowing one event does not change the probability of the other. Use an exact relation, such as the intersection probability equalling the product of the marginal probabilities
- Find the intersection Calculate the probability that both events occur together \(\displaystyle \Pr(A\cap B)=\frac{4}{20}=\frac{1}{5}\)
- Find the marginal probabilities Calculate the probability of each event from the full sample space \(\displaystyle \Pr(A)=\frac{8}{20}=\frac{2}{5},\quad\Pr(B)=\frac{10}{20}=\frac{1}{2}\)
- Multiply the marginals The comparison value is the product of the separate event probabilities \(\displaystyle \Pr(A)\times\Pr(B)=\frac{2}{5}\times\frac{1}{2}=\frac{1}{5}\)
- Compare exact values Equal values mean independent and unequal values mean dependent \(\displaystyle \frac{1}{5}=\frac{1}{5}\Rightarrow\text{independent}\)
Worked example
A finite sample space has 24 equally likely outcomes. Event A contains 12 outcomes, event B contains 8 outcomes, and 4 outcomes are in both events. Test whether A and B are independent
- \(\displaystyle \Pr(A\cap B)=\frac{4}{24}=\frac{1}{6}\)Use the 4 outcomes in both events over the 24 outcomes in the sample space
- \(\displaystyle \Pr(A)=\frac{12}{24}=\frac{1}{2}\)Use the 12 outcomes in event A over the full sample space
- \(\displaystyle \Pr(B)=\frac{8}{24}=\frac{1}{3}\)Use the 8 outcomes in event B over the full sample space
- \(\displaystyle \Pr(A)\times\Pr(B)=\frac{1}{2}\times\frac{1}{3}=\frac{1}{6}=\Pr(A\cap B)\Rightarrow\text{independent}\)The exact comparison values are equal, so the events are independent
Common mistakes
Difficulty levels
Questions about this topic
What does independence mean?+
Two events are independent when the occurrence of one does not change the probability of the other
Why is the product used in the independence test?+
For independent events, the probability of both occurring equals the product of their separate probabilities
Are mutually exclusive events independent?+
Not when both events have positive probability. Their intersection is zero but the product of their marginal probabilities is positive
Can I use a calculator?+
A calculator is allowed unless a question is marked no calculator
Which year level and chapter is this?+
Year 11, VCE Units 1 & 2, Mathematical Methods, chapter 8: Probability and counting