Polynomial values and coefficient parameters
To evaluate a polynomial, substitute the input into every term and keep signed inputs in brackets. To find a coefficient parameter, turn each stated polynomial value or remainder into an exact equation
- Substitute in every term Replace every occurrence of the variable by the stated input \(\displaystyle P(x)=2x^2-3x+1\Rightarrow P(2)=2(2)^2-3(2)+1\)
- Keep brackets around signed inputs Use brackets so the sign is included when a power is evaluated \(\displaystyle (-3)^2=9,\qquad -3^2=-9\)
- Evaluate powers first Find each required power before multiplying by its coefficient and combining terms \(\displaystyle P(-1)=2(-1)^2-3(-1)+1=6\)
- Turn conditions into equations For an unknown coefficient, substitute the stated input and solve the resulting exact equation \(\displaystyle P(x)=x^2+px+1,\quad P(2)=11\Rightarrow4+2p+1=11\Rightarrow p=3\)
Worked example
Evaluate the polynomial at the stated input
- \(\displaystyle P(-1)=3(-1)^3-2(-1)^2+4(-1)-5\)Replace every t by -1 and keep brackets around the signed input
- \(\displaystyle (-1)^3=-1,\qquad (-1)^2=1\)Evaluate the powers before combining the terms
- \(\displaystyle P(-1)=3(-1)-2(1)+4(-1)-5=-3-2-4-5=-14\)Multiply each power by its coefficient and add the resulting terms
Common mistakes
Difficulty levels
Questions about this topic
What does P(a) mean?+
P(a) is the value of the polynomial when every occurrence of the variable is replaced by a.
Why are brackets needed around a negative input?+
Brackets show that the negative value is the base of the power. Squaring negative two gives four; squaring two and then negating gives negative four
How is a coefficient parameter found from P(a)?+
Substitute a into every term, set the expression equal to the stated value, and solve the resulting equation for the parameter
Can I use a calculator?+
No. This topic is practised without a calculator
Which year level and chapter is this?+
Year 12, VCE Units 3 & 4, Mathematical Methods, chapter 6: Applications of differentiation