Equivalent polynomial forms
An equivalent polynomial form has the same value for every allowed value of the variable. Distribute carefully when expanding and select a factor pattern that can be verified by multiplication
- Distribute through every term Multiply the outside factor by each term inside the bracket \(\displaystyle 3\left(x+4\right)=3x+12\)
- Collect like powers only Terms can be combined only when their variable parts have the same powers \(\displaystyle 2x^2+3x\ne5x^2\)
- Use the matching factor pattern Choose a factorisation pattern that reproduces the original polynomial when expanded \(\displaystyle x^2-25=\left(x-5\right)\left(x+5\right)\)
- Restore and verify the structure Multiply the factors or expand the brackets to check that the original expression is recovered \(\displaystyle \left(x+2\right)^2=x^2+4x+4\)
Worked example
Expand and simplify the polynomial product below
- \(\displaystyle 2x\times x=2x^2,\quad2x\times4=8x\)Multiply the first term in the first bracket by both terms in the second bracket
- \(\displaystyle -3\times x=-3x,\quad-3\times4=-12\)Multiply the second term in the first bracket by both terms in the second bracket
- \(\displaystyle 2x^2+8x-3x-12=2x^2+5x-12\)Collect the two like x terms to obtain the equivalent polynomial form
Common mistakes
Difficulty levels
Questions about this topic
What makes two polynomial forms equivalent?+
They produce the same value for every value of the variable for which both expressions are defined
Which terms are like terms?+
Like terms have exactly the same variables raised to the same powers, although their coefficients may differ
How can a factorisation be checked?+
Expand the factors and compare the result with the original polynomial
Can I use a calculator?+
No. This topic is practised without a calculator
Which year level and chapter is this?+
Year 12, VCE Units 3 & 4, Mathematical Methods, chapter 12: Continuous probability distributions