Amounts and rates in an exponential model
Read the initial amount, differentiate with the inner coefficient, then evaluate or solve the requested quantity
- Amount versus rate A has amount units; A′ has amount per time units. k has inverse-time units
- Use a ratio for two observations Cancel A₀ with A(t₂)/A(t₁), take ln and divide by t₂ − t₁
- Check domains and signs Positive k gives growth; negative k gives decay. Positive amounts are required for logarithms; time must satisfy the stated model domain
- Round once Keep exact fractions and logarithms until a decimal answer is requested. Retain calculator precision before the final rounding
Worked example
A mass is M(t) = 180e^(−t/30) grams, with t in minutes. Find its signed rate at 6 min and the exact time when it reaches 90 g.
- \(\displaystyle M^{\prime}(t)=180(-1/30)e^{-t/30}=-6e^{-t/30}\)Differentiate with the inner coefficient
- \(\displaystyle M^{\prime}(6)=-6e^{-1/5}\approx-4.91\text{ g/min}\)At 6 min the mass is decreasing at about 4.91 g/min.
- \(\displaystyle 180e^{-t/30}=90\quad\Rightarrow\quad e^{-t/30}=1/2\)Use the amount equation for the target mass
- \(\displaystyle t=-30\ln(1/2)=30\ln2\text{ min}\)Take ln and divide by −1/30. This positive time is in the domain
Common mistakes
Difficulty levels
Questions about this topic
Does selecting a logarithmic expression prove I can construct the whole model?+
No. The choices check recognition; the numeric steps check individual values. Full independent modelling needs additional evidence
Does the lesson cover calculator procedures?+
It practises evaluating and rounding a stated expression. It does not assess a complete calculator workflow or all technology outcomes
Why is a negative target time sometimes rejected?+
It may solve the algebraic equation but lie outside the stated physical time domain
Can I use a calculator?+
A calculator is allowed unless a question is marked no calculator
Which year level and chapter is this?+
Year 12, VCE Units 3 & 4, Mathematical Methods, chapter 5: Differentiation