Binary means and exact finite sampling
A proportion is a mean of indicator values
- Mean For zero–one records, divide the number of successes by the sample size to find the mean
- Without replacement Count equally likely labelled samples and group by statistic
- Probability Divide a group’s count by all possible samples
- Scope A binary table is a special case, not all numerical sample-mean distributions
Worked example
Select three of six labelled records without replacement: two ones and four zeros. Find the probability that the sample mean is one third
- \(\displaystyle \Pr(\overline X=\tfrac13)=\frac{\binom21\binom42}{20}=\frac{2\times6}{20}=\frac{12}{20}=\frac35\)A sample mean of one third means one success. The sample count determines the probability; three possible mean values do not imply a probability of one third each
Common mistakes
Difficulty levels
Questions about this topic
Can the sample mean take a value absent from the population?+
Yes. A mean such as 1/3 need not be an individual record value
Can I use a calculator?+
No. This topic is practised without a calculator
Which year level and chapter is this?+
Year 11, VCE Units 1 & 2, Specialist Mathematics, chapter 6: Random variables and sampling