Propositions, quantifiers and counterexamples
State the domain and the exact claim before choosing a witness, negation or proof method
- State the domain A proposition has a definite truth value, true or false. A predicate such as x² = 4 is open until x is assigned or quantified over a stated domain
- Every and at least one The universal quantifier means every member of the domain. The existential quantifier means at least one member, not exactly one. A witness must belong to the domain \(\displaystyle \begin{gathered}\forall x\in D,\ P(x)\\\exists x\in D,\ P(x)\end{gathered}\)
- Negate both the quantifier and the predicate Not every means at least one failure. There does not exist means every member fails. Keep the same domain and include the correct inequality boundary \(\displaystyle \begin{gathered}\neg(\forall x\in D, P(x))\\\iff\exists x\in D,\neg P(x)\\\neg(\exists x\in D, P(x))\\\iff\forall x\in D,\neg P(x)\end{gathered}\)
- A conditional has one failure case To disprove if P then Q, make P true and Q false. A false hypothesis is not a counterexample. The negation of the conditional is P and not Q. \(\displaystyle \begin{gathered}\neg(P\implies Q)\\\iff P\land\neg Q\end{gathered}\)
- Distinguish the related conditionals The converse reverses the direction and need not be equivalent. The contrapositive reverses the direction and negates both statements; it is equivalent to the original \(\displaystyle \begin{gathered}\text{original: }P\implies Q\\\text{converse: }Q\implies P\\\text{contrapositive: }\neg Q\implies\neg P\end{gathered}\)
- Sufficient and necessary In P implies Q, P is sufficient for Q, while Q is necessary for P. An equivalence, written if and only if, requires both directions \(\displaystyle P\iff Q\)
- Use examples for the right purpose One verified witness proves existence. One valid counterexample refutes a universal claim. Successful examples do not prove an infinite universal claim; a finite domain can be proved by checking every member
- Quantifier order matters In for every x there exists y, y may depend on x. In there exists y for every x, one fixed y must work for all x. Negation changes each quantifier in place; it does not reorder them
Worked example
Negate and refute the claim: every real x satisfying x² > 16 also satisfies x > 4.
- \(\displaystyle \begin{gathered}\forall x\in\mathbb R:\\x^2>16\implies x>4\end{gathered}\)Identify the domain, hypothesis and conclusion
- \(\displaystyle \begin{gathered}\exists x\in\mathbb R:\\x^2>16\text{ and }x\le4\end{gathered}\)The negation requires a true hypothesis and a false conclusion for one allowed value
- \(\displaystyle x=-5\in\mathbb R\)Choose a value in the domain
- \(\displaystyle \begin{gathered}(-5)^2=25>16\\-5\le4\end{gathered}\)Verify both parts. The existential negation is true, so the original universal claim is false
Common mistakes
Difficulty levels
Questions about this topic
Does there exists mean exactly one?+
No. It means at least one. A unique witness is a stronger claim that must be stated separately
Is the contrapositive always true?+
No. It has the same truth value as the original implication. If the original is false, the contrapositive is false too
Can a computer search prove a universal statement?+
It can if it exhausts a genuinely finite stated domain, or implements a justified proof procedure. Testing a finite initial segment of an infinite domain alone is not a general proof
Why is a universal statement over an empty domain true?+
No member violates it. This does not establish an existential statement, which needs an actual member as a witness
What is automatically assessed?+
Only selected interpretations and proof-related substeps receive activity feedback. The 24-case finite bank awards no aggregate proficiency or automatic tier promotion. Full written construction and justification are ungraded
Can I use a calculator?+
No. This topic is practised without a calculator
Which year level and chapter is this?+
Year 11, VCE Units 1 & 2, Specialist Mathematics, chapter 1: Number, sets and proof