Brackets and common denominators
Choose operations that preserve the entire equation. Explain each transformation rather than moving isolated symbols
- Distribute signs Multiply every term inside each bracket, including negative constants
- Clear every term Use a non-zero common multiple of numerical denominators. Multiply whole-number terms too
- Keep subtracted numerators grouped After cancelling a denominator, an outside minus still acts on the whole numerator
- Check original values Keep an exact fraction and substitute into the original brackets and denominators. If unknown terms cancel, classify the remaining equality
Worked example
Solve a difference of two fractions and check it
- \(\displaystyle 2(x+1)-3(x-2)=6\)Multiply every term by 6.
- \(\displaystyle 2x+2-3x+6=6\)Expand both complete numerators with their signs
- \(\displaystyle -x+8=6\)Collect like terms
- \(\displaystyle x=2\)Subtract 8 and divide by −1.
- \(\displaystyle \frac{2+1}{3}-\frac{2-2}{2}=1\)Substitute into the original equation
- \(\displaystyle 1-0=1\)Both sides agree
Common mistakes
Difficulty levels
Questions about this topic
Do I always expand first?+
No. Isolating a single bracket by division can be shorter. Both routes are valid when the operation applies to the whole of both sides
Why use the lowest common denominator?+
Any non-zero common multiple works. The lowest positive common multiple of numerical denominators usually keeps the arithmetic smaller
Can I cross multiply a sum?+
Only after treating each whole side correctly. The reliable method is to multiply every term by a common denominator. Never ignore an extra term
What if a denominator contains the unknown?+
State the original forbidden values first and check candidates in the original equation. The fraction-equation topic in this section practises that extension
Can I use a calculator?+
No. This topic is practised without a calculator
Which year level and chapter is this?+
Year 10 Mathematics, chapter 8: Linear equations and inequalities