Rationalising surd denominators
Rationalise a denominator by multiplying the numerator and denominator by a suitable factor. Use a conjugate for a binomial and simplify the exact result afterwards
- Multiply top and bottom by the same factor Multiplying the numerator and denominator by the same non-zero factor preserves the value \(\displaystyle \frac{a}{b}=\frac{a\times k}{b\times k}\)
- Use the radical for a monomial For a denominator with one square root, multiply by that same square root \(\displaystyle \frac{1}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}}=\frac{\sqrt{3}}{3}\)
- Use the sign-switched conjugate For a binomial denominator, switch the sign between its rational and surd terms \(\displaystyle \left(5+2\sqrt{3}\right)\left(5-2\sqrt{3}\right)=25-12=13\)
- Reduce the final exact form Simplify numerical factors and remove any square factors from a surd radicand \(\displaystyle \frac{3\sqrt{2}}{6}=\frac{\sqrt{2}}{2}\)
Worked example
Rationalise and simplify the denominator in the fraction below
- \(\displaystyle \frac{3}{4+\sqrt{7}}\times\frac{4-\sqrt{7}}{4-\sqrt{7}}\)Multiply top and bottom by the conjugate of the denominator
- \(\displaystyle \left(4+\sqrt{7}\right)\left(4-\sqrt{7}\right)=4^{2}-\left(\sqrt{7}\right)^{2}=16-7=9\)The conjugate product removes the surd from the denominator
- \(\displaystyle 3\left(4-\sqrt{7}\right)=12-3\sqrt{7}\)Expand the numerator after applying the same conjugate factor
- \(\displaystyle \frac{12-3\sqrt{7}}{9}=\frac{4-\sqrt{7}}{3}\)Divide each numerator term by 9 and reduce the common factor 3
Common mistakes
Difficulty levels
Questions about this topic
What is a conjugate in surd rationalisation?+
The conjugate keeps the rational term and switches the sign of the surd term in a binomial
Why do the cross terms disappear when conjugates are multiplied?+
The two cross terms have equal magnitude and opposite signs, leaving a difference of squares
What is a rational denominator?+
It is a denominator that contains no surd or other irrational term
Can I use a calculator?+
No. This topic is practised without a calculator
Which year level and chapter is this?+
Year 11, VCE Units 1 & 2, Mathematical Methods, chapter 2: Algebraic foundations