Factorials and combinations
Specify whether positions or only membership matter
- Ordered, without repetition For a valid selection size \(\displaystyle \frac{n!}{(n-k)!},\qquad 0\le k\le n\)
- Unordered, without repetition Count each selected group once \(\displaystyle \binom{n}{k}=\frac{n!}{k!(n-k)!}\)
- Boundary The empty and complete selections each have one outcome \(\displaystyle \binom{n}{0}=\binom{n}{n}=1,\qquad 0!=1\)
Worked example
Compare assigning two different roles to nine people with selecting an unlabelled pair
- \(\displaystyle {}_9P_2=72\)Role order matters
- \(\displaystyle \binom92=\frac{72}{2!}=36\)Each pair has two role assignments
Common mistakes
Difficulty levels
Questions about this topic
Does C(n,k) allow repeated objects?+
No. It selects k different members of an n-element set. Unlimited repeated types need a different count
Can I use a calculator?+
No. This topic is practised without a calculator
Which year level and chapter is this?+
Year 11, VCE Units 1 & 2, Specialist Mathematics, chapter 4: Discrete mathematics