Linear combinations
Keep variable identity, coefficient signs and joint assumptions explicit
- Mean The mean of a constant plus a weighted sum is the constant plus the sum of each weight times its variable’s mean, regardless of independence
- Independent variance For independent variables, the variance of a constant plus a weighted sum is the sum of each squared weight times its variable’s variance. The standard deviation is the positive square root
- Normal inputs Independent normals give a normal combination when its variance is positive
- Repeated source Collect coefficients of the same variable before using independence
- Probability Standardise each boundary using the combined mean and standard deviation; round at the end
Worked example
Independent normal variables X and Y have means 50 and 30 and variances 9 and 16, respectively. Find the probability that X exceeds Y by more than 25
- \(\displaystyle X-Y\sim N(20,25)\)Subtract the means but add the independent variances
- \(\displaystyle z=\frac{25-20}{5}=1\)Use the combined standard deviation of 5
- \(\displaystyle \Pr(Z>1)=1-\Phi(1)\approx0.1587\)Take the upper tail and round to four decimal places
Common mistakes
Difficulty levels
Questions about this topic
Must the inputs be identically distributed?+
No. Keep each variable’s own mean and variance
Is an independent sum always normal?+
No. The exact normal combination theorem used here assumes independent normal inputs
What if both coefficients are zero?+
The result is constant. Its variance is zero and ordinary standardisation is undefined
Can I use a calculator?+
A calculator is allowed unless a question is marked no calculator
Which year level and chapter is this?+
Year 12, VCE Units 3 & 4, Specialist Mathematics, chapter 8: Probability and statistical inference