Sampling means and standard error
State the sampling model before using its distribution
- iid finite variance E(X̄)=μ, Var(X̄)=σ²/n and SE=σ/√n.
- Normal population The iid mean is exactly normal for every positive n.
- Non-normal population A normal approximation is a large-sample limit; adequacy depends on shape and tails
- Estimated SE When σ is unknown, s/√n estimates the standard error
- Simulation n observations form one mean; R repetitions produce R means
Worked example
Independent observations have a normal distribution with mean 18 and variance 36. For a sample of size 16, find the probability that the sample mean exceeds 21
- \(\displaystyle \operatorname{SE}=6/\sqrt{16}=3/2\)Use the SD of the mean
- \(\displaystyle z=(21-18)/(3/2)=2\)Standardise the sample-mean event
- \(\displaystyle \Pr(\overline X>21)=1-\Phi(2)\approx0.0228\)Take the upper tail and round at the end
Common mistakes
Difficulty levels
Questions about this topic
Can an individual sample mean differ from μ?+
Yes. E(X̄)=μ describes repeated sampling, not each realised mean
Does more data fix selection bias?+
No. The target population and selection mechanism still matter
Does σ²/n apply without replacement?+
Not exactly in general for a finite population; the draws are dependent, and a census has zero sampling spread
Can I use a calculator?+
A calculator is allowed unless a question is marked no calculator
Which year level and chapter is this?+
Year 12, VCE Units 3 & 4, Specialist Mathematics, chapter 8: Probability and statistical inference