Sampling means and standard error
State the sampling model before using its distribution
- iid finite variance The sample mean has expected value μ, variance equal to the population variance divided by n, and standard error equal to the population standard deviation divided by the square root of n
- Normal population The iid mean is exactly normal for every positive n
- Non-normal population A normal approximation is a large-sample limit; adequacy depends on shape and tails
- Estimated SE When σ is unknown, s/√n estimates the standard error
- Simulation n observations form one mean; R repetitions produce R means
Worked example
Independent observations follow a normal distribution with mean 18 and variance 36. For a sample of 16, find the probability that the sample mean exceeds 21
- \(\displaystyle \operatorname{SE}=6/\sqrt{16}=3/2\)Use the SD of the mean
- \(\displaystyle z=(21-18)/(3/2)=2\)Standardise the sample-mean event
- \(\displaystyle \Pr(\overline X>21)=1-\Phi(2)\approx0.0228\)Take the upper tail and round at the end
Common mistakes
Difficulty levels
Questions about this topic
Can an individual sample mean differ from μ?+
Yes. E(X̄)=μ describes repeated sampling, not each realised mean
Does more data fix selection bias?+
No. The target population and selection mechanism still matter
Does σ²/n apply without replacement?+
Not exactly in general for a finite population; the draws are dependent, and a census has zero sampling spread
Can I use a calculator?+
A calculator is allowed unless a question is marked no calculator
Which year level and chapter is this?+
Year 12, VCE Units 3 & 4, Specialist Mathematics, chapter 8: Probability and statistical inference